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I need help I am completely lost can anyone help me with this problem: Here is a

ID: 3202560 • Letter: I

Question

I need help I am completely lost can anyone help me with this problem:

Here is an incomplete syntax command below based on " Exercise 3.7: Finding Proportions of Observations Below a Specified Z Score (Standard Normal Distribution) Now, we will turn our attention to finding the percentage of observations that lie below a specific z-score. This can be done using Table Z in your book for one observation at a time, but if you want to check hundreds of scores all at once, a program such as SPSS is far more efficient. Compute the proportion of observations that lie below a specified z value. Using Syntax: Run this syntax command: COMPUTE BelowP = CDF.NORMAL ([Variable label],0,1). EXECUTE. When choosing the variable name, you should consider that you would like to start with a set of z-scores and find the proportion that lie below as output. Study your Data Editor window and choose an appropriate variable from your five options (Hint: Only two of your variables are z-scores). Insert the proper variable label and then highlight and run the syntax selection. Your output will appear in the Data Editor window. In case you are interested, cdf.normal is the cumulative density function for the normal distribution. For any single subject, the quantity P(Xx) is the cdf: X is a random variable because its value can vary from day to day and it cannot be predicted with certainty while x is any given observation value within the data set"

Can you compute this for me:incomplete syntax command

COMPUTE AboveP = ABS(CDF.NORMAL (Variable label,0,1)-1). EXECUTE. Fill in the new arguments. Then select and run the syntax command. FYI, ABS is the command to take the absolute value.

I need as soon as possible

Explanation / Answer

without the data it is difficult to tell you the exact command , however i can guide you how the syntax cdf.normal is configured that shall help you in arriving at the desired result

cdf.normal(?,?,?) is the standard format

first ? is the measurement second ? is the mean and thethe third ? is the standard deviation

so if you are working with z scores and need to find the area between z=-0.1 and Z = 1.45 then you shall formulate the expression as

cdf.normal(?,?,?) - cdf.normal(?,?,?) , now recall that mean and sd of standard normal is 0 and 1

so cdf.normal(1.45,0,1) - cdf.normal(-0.1,0,1) , this will give you the exact area you need lying between the two assumed z scores

also the left tail area for z = 1.45 is given as

cdf.normal(1.45,0,1)

right tail is 1 - left tail

1- cdf.normal(1.45,0,1)

and if you want a 2 tail area then add both the above results as

2*cdf.normal(1.45,0,1)

Hope this helps

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