samples of skin experiencing desquamation are analyzed forboth moisture and mela

Question

samples of skin experiencing desquamation are analyzed forboth moisture and melanin content. the results from 100 skinsamples are as follows:

                                                       melanin content

                                                      high                    low

moisture                high                   13                     7

content                   low                    48                  32

let A denote the event that a sample has low melanin content,and let B denote the event that a sample has high moisture content.determine the following probabilities:

a)P(A)             b) P(B)

c)P(A|B)          d) P(B|A)

Explanation / Answer

A =event that a sample has low melanin content

B =event that a sample has high moisture content

a) P(A)= (7+32)/100=39%

b) P(B)=(13+7)/100=20%

c) P(A|B)=P(A and B)/P(B)= 7/20=35%

d) P(B|A)=P(A and B)/P(A)=7/39=17.95%

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