A candy company claims that 24 percentage of its plain candies are orange, and a

Question

A candy company claims that 24 percentage of its plain candies are orange, and a sample of 100 such candies is randomly selected. Find the mean and standard deviation for the number of orange candies in such groups of 100. mu = sigma = (Round to one decimal place as needed.) A random sample of 100 candies contains 23 orange candies. Is this result unusual? Does it seem that the claimed rate of 24 percentage is wrong? Yes. because 23 is below the minimum usual value. Thus, the claimed rate of 24 percentage is probably wrong. Yes. because 23 is within the range of usual values. Thus, the claimed rate of 24 percentage is probably wrong. No. because 23 is within the range of usual values. Thus, the claimed rate of 24 percentage is not necessarily wrong. Yes. because 23 is greater than the maximum usual value. Thus, the claimed rate of 24 percentage is not necessarily wrong.

Explanation / Answer

a. mean=n*p where n=100 and p=0.24. thus mean=24

standard deviation is square root of variance. variance is n*p*(1-p) =24*(1-0.24)=18.24

thus sd=sqrt(18.24)=4.3

b. The answer is C.

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