A fruit was collected from each of eight lemon trees, with the intent of measuri

Question

A fruit was collected from each of eight lemon trees, with the intent of measuring the calcium concentration in the rind (grams of calcium per 100 grams of dry rind). The analytical method used could only detect a concentration of at least 0.80g/100g of dry weight.
Six of the eight concentrations were measured to be 1.02, 0.98, 0.91, 0.84, 0.87, 1.04g.100 g of dry weight, and two of the concentrations were known to be less than 0.80g/100 g of dry weight. What is the median of this sample of eight data? Can you also get the mean?

I don't want just the answer- a step by step explanation of how to do this would be great.
I tried doing it myself and got .8125 but that clearly can not be the median. Thank you so much!

Explanation / Answer

To find the median:

First arrange the data in ascending order:

a,b, 0.84, 0.87, 0.91, 0.98, 1.02, 1.04,

where a and b are the two numbers which are less than 0.80

There are in total 8 values.

Median is middle most item.

Here, 4 and 5 are the middle items.

So, median = (4th item + 5th item)/2 = (0.87 + 0.91 )/2 = 0.89

Mean cannot be got, because for calculation of mean, exact value of all the 8 concentrations are needed. But, here, exact values of two concentrations of less than 0.80 are not not known.

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