There are multiple alleles that determine eye color in rabbits; a^+ encodes red

Question

There are multiple alleles that determine eye color in rabbits; a^+ encodes red eyes, a^b encodes brown eyes, and a^w encodes white eyes. These alleles display complete dominance and are presented in their order of dominance {a^+ > a^b > a^w} If an individual were a^+/a^b, what color would their eyes be? So, if you mated that a^+/a^b individual with one that has white eyes, what are the odds of having a brown eyed bunny? A novel mutation of the gene that produces yellow eyes (a^y) is codominant with a^+. So what would an a^+/a^y Individual look like?

Explanation / Answer

a+/ab is red eyes

a+/ab x aw/aw = a+/aw, a+aw, ab/aw, ab/aw; the odds of brown eyed bunny=½

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.