Landolt et al. (A-26) examined rates of posttraumatic stress disorder (PTSD) in

Question

Landolt et al. (A-26) examined rates of posttraumatic stress disorder (PTSD) in mothers and fathers. Parents were interviewed 5 to 6 weeks after an accident or a new diagnosis of cancer or diabetes mellitus type I for their child. Twenty-eight of the 175 fathers interviewed and 43 of the 180 mothers interviewed met the criteria for current PTSD. Is there sufficient evidence for us to conclude that fathers are less likely to develop PTSD than mothers when a child is traumatized by an accident,
cancer diagnosis, or diabetes diagnosis? Let type 1 error rate = .0.05

Please do the 10 step hypothesis testing procedure and write out the calculations. Do NOT use "Minitab"

Explanation / Answer

here null hypothesis: difference in proportion p1-p2=0

alternate hypothesis: p1<p2

critcal value of z at 0.05 level =-1.6449

here p1=28/175=0.16 ' p2=43/180=0.239

hence std error =(p1(1-p1)/n1 +p2(1-p2)/n2)1/2=0.042

therefore test stat z=(p1-p2)/std error =-1.8708

fopr above z pvalue =0.0307

as p value is less then 0.05 level and z stat value is outside crtical region we reject null hypothesis, and conclude that fathers are less likely to develop PTSD than mothers when a child is traumatized by an accident

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