sample proportion is 201/300=0.67 Step 3: Assess the Evidence 3 Let\'s use the r
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sample proportion is 201/300=0.67
Step 3: Assess the Evidence 3 Let's use the reporter's sample proportion to test her claim. A On the normal curve below plot the assumed population proportion identified in the null hypothesis and the sample proportion computed in Question 2A above. 8 8 8 R R R B The P-value is the probability of randomly observing a sample proportion at least as extreme (in this case, large) as the one gathered in our sample. Shade the area under the normal curve above that corresponds to this probability. statway version 3.0, 2016 The Carnegie Foundation for the Advancement of Teaching 7.3.1 I 12Explanation / Answer
A. The population propotion, p=0.65.
B. The p value corresponds to area at the right of the curve about 0.69 corresponding to this probability.
C. Mean, muphat=p
=0.65
Standard error, sigma phat=sqrt[p(1-p)/n]
=sqrt[0.65(1-0.65)/300]
=0.0275
D. The Z score of sample proportion,
Z=phat-muphat/sigmaphat
=(0.67-0.65)/0.0275
=0.73
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