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Question

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https://dl.dropboxusercontent.com/u/148382/SUPublic/Statistics%20Non%20Credit/HoozYourCandies.xlsx

Based on historical data, your team knows what proportion of the company's orders come from Males (and Females). However, your team would like to expand its sales so that men are more proportionately represented. By the end of this year, you think you would like your total proportion of sales to males to be at least 0.46. If you took a simple random sample of 85 current orders, what is the probability that the sample proportion of male customers is greater than 0.46?

Note: You should carefully round any intermediate calculations to 4 decimal places to match wamap's approach and calculations.

Explanation / Answer

Normal Distribution
Proportion ( P ) =0.46
Standard Deviation ( sd )= Sqrt (P*Q /n) = Sqrt(0.46*0.54/85)
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
P(X > 0.46) = (0.46-0.46)/0.0541
= 0/0.0541 = 0
= P ( Z >0) From Standard Normal Table
= 0.5                  

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