For sales promotion, a manufacturer places winning symbols under the caps of 10%

Question

For sales promotion, a manufacturer places winning symbols under the caps of 10% of all Pepsi bottles. Assume winning symbols are placed independently. You buy an eight-pack. Answer the following questions. What is the Probability that there will be no winning symbol under a cap of randomly selected bottle produced by this manufacturer? 0.1 0.9 None of the above: What is the Probability that you will not win at all? 0.43 0.9 0-57 None of the above What is the Probability that you will win at least once? 0.1 0.43 0.57 None of the above

Explanation / Answer

4. On selecting 1 random bottle,

P(no winning symbol) = 1 - 0.10 = 0.9

Answer = 0.9

5. Number of winning symbols (X) follows binomial distribution with n=8 and p=0.10

P(X=0) = 8C0 * 0.100 * (1-0.10)8-0 = 0.43

Answer = 0.43

6. P(X >= 1) = 1 - P(X=0)

= 1 - 0.43 = 0.57

Answer = 0.57

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