Question
1 and 2 please. please explain in detail walk through part e)
CHAPTER sa noose the to the last sentence is change to read Does this evider that the mean amount sed is more than 16 ounces? State the null hypot dispens conditions, (a)? ou IEW is the under these stated in part 16.040 What rule under the new ditions mean to be A A second sample of 50 filled containers reveal the the value of the test for this sample? what is your decision regarding the null statistical test. hypothesis based el in a single sentence, the result of the null What is the p-value? What your regarding the Is this the same co reached (d)? p-value? For Exercises 1-4, answer the questions: (a) ls this a one- or test? (b) What decision What is the value of the test statistic? What is your decision What is the p-value? it. 1. selected from normal The sample mean a hypothesis and the population standard deviation is Conduct the following test of is the .05 50 H1: 50 A sample of 36 observations is selected from a normal population. The sample mean is12 and the population standard deviation is 3. Conduct the following test of hypothesis using the .01 significance level. Ho: s 10 Hi: 10
Explanation / Answer
1) here it is two tailed test.
for which at 0.05 level , critical value of z =+/- 1.96
here std error =std deviation/(n)1/2=0.833
hence test stat =(X-mean)/std error =(49-50)/0.833=-1.2005
as test stat falls inside the acceptance region we can not reject null hypothesis.
2) here it is one tailed test.
for which at 0.01 level, critical value of z =2.3263
here std error =std deviation/(n)1/2=0.5
test stat z=(X-mean)/std error =(12-10)/0.5=4
as test stat is inside critical region(rejection region), we reject null hypothesis.
