If a person has a rare disease, then a diagnostic test for that disease detects
ID: 3209300 • Letter: I
Question
If a person has a rare disease, then a diagnostic test for that disease detects it with probability 99%. If a person does not have the disease, then the test reports that she does not have the disease with probability 95%. Only 0.5% of the population has the disease. a) If the test reports a positive result for a person selected at random from the population, find the probability that this person actually has the disease. b) To improve the value of probability in part a, which is better: reducing false positives by 20% or reducing false negatives by 20%? Explain your answer.Explanation / Answer
Have disease (0.5%)
Do not have disease (99.5%)
Test Positive
0.99
0.05
Test Negative
0.01
0.95
P (True Positive) =0.99*0.005=0.00495
P (True negative) =0.95*0.995=0.94525
P (False Positive) =0.05*0.995=0.04975
P (False negative) =0.005*0.01=0.00005
a)
0.00495/(0.00495+0.04975)
0.00495/0.0547
0.09
b)
Reducing false positives by 20% would give a better probability because the value of denominator would decrease and consequently the value of probability would go up.
Have disease (0.5%)
Do not have disease (99.5%)
Test Positive
0.99
0.05
Test Negative
0.01
0.95
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