Directions: For full credit on solved problems you must show·logical progression
ID: 3209837 • Letter: D
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Directions: For full credit on solved problems you must show·logical progression of mathem.ice-eale.ay assumptions. You will be penalized for messy and irrational writings. English grammae and will be graded. I will take off for sloppy sentences or sentences that do not make sense. WRITE NEATLY . 0.0000000000000000000000000000000000000001- 1 x 10* where s- 2. Voltage is similar to water while current is akin to water refully the (6 points) bulb, V 4. In a series circuit shown below, using Ohms' Law, calculate the voltage drop across the the circuit is shown as I and has a value of The bulb resistance R is 10 Ohms. The current 2 Amperes (A). (20 pts). Remember to show all your work for full credit flowing in - VpeteryExplanation / Answer
1-value of x will be -43 because there are 42 zero after decimal .
as 0.00004= 4*10^(-5)
3-Voltage and current are the cornerstone concepts in electricity.Current is reported as the number of charges per unit time passing through a boundary
Since current is the amount of charge passing through a boundary in a fixed amount of time, it can be expressed mathematically using the following equation:
i = dq/dt
We define voltage as the amount of potential energy between two points on a circuit. One point has more charge than another. This difference in charge between the two points is called voltage. It is measured in volts, which, technically, is the potential energy difference between two points that will impart one joule of energy per coulomb of charge that passes through it.
We can express the voltage between two points mathematically as the change of energy experienced by a charge:
V = delta U/q.
4- from ohm law we get
V=IR, GIVEN i= 2 amp, r= 10 ohm
v=2*10= 20 volts
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