Two ships leave the same port at noon. Ship A sails north at 19 mph, and ship B

Question

Two ships leave the same port at noon. Ship A sails north at 19 mph, and ship B sails east at 15 mph. How fast is the distance between them changing at 1 p.m.?

Explanation / Answer

1) Two ships leave the same port at noon. Ship A sails north at 15 mph, and ship B sails east at 12 mph. How fast is the distance between them changing at 1PM? 2) Two ships leave the same port at noon. Ship A sails north at 15 mph, and ship B sails east at 12 mph. How fast is the distance between them changing at 2PM whats is the differnece?>?? d^2 = x^2 + y^2 Differentiate with respect to time, 2dd' = 2xx' + 2yy' d' = (xx'+yy')/d 1) d' = (15^2+12^2)/(3sqrt(41)) = 19.2 mph 2) d' = 2(15^2+12^2)/(2*3sqrt(41)) = 19.2 mph So, there is no difference in relative speed between the two ships. Actually, using vector approach, you can get the answer much easier. d ' = sqrt(u^2+v^2) = sqrt(12^2+15^2) = 19.2 mph

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