A source is emitting a sound of frequency f Hz (cycles per second). You begin at

Question

A source is emitting a sound of frequency f Hz (cycles per second). You begin at the location P in the picture and travel in a line as pictured to the left at v mph. Note the angle ? in the picture. The sound you will hear has perceived frequency F according to the formula:

F=

In this formula, the number "761" is coming from the fact that the speed of sound in air is approximately 761 mph. Give exact answers to all parts below. Assume that d=30 miles.

(a) We can view the perceived frequency F as a function of time t hours where the formula for F(t)= ???

(b) F(0)=???

(d) For the value of v= ?? the perceived sound has frequency t/2 as t goes to infinity. (In practical terms, this means the perceived sound is an octave LOWER than the original sound for large t.)

Explanation / Answer

phase difference for sound to travel ,a=(d^2+(vt)^2)^.5 -d so F=f/1=v/760 *cos(wt-a)

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