Cameron is located 2 miles due East of an intersection between two country roads

Question

Cameron is located 2 miles due East of an intersection between two country roads. He decides to walk in a straight line (cross-country) toward a position 3 miles due North of the intersection; it takes Cameron one hour to reach that location. The formula for the distance between Cameron and the intersection at time t hours is d(t) = At time t=1 hour, the (instantaneous) rate of change of the distance between Cameron and the intersection mph(give an exact answer). If v(t)=d'(t) is the instantaneous rate of change of d(t) at time t, then lim t rightarrow infinity v(t) = (give an exact answer) If v(t)=d'(t) is the instantaneous rate of change of d(t) at time t, then lim t rightarrow 0+ v(t) = (give an exact answer) At time hours (give an EXACT answer), the (instantaneous) rate of change of the distance between Cameron and the intersection is 0 mph.

Explanation / Answer

given d(t) = sqrt((2-2t)^2 + (3t)^2) a) rate of change of d(t) = dd(t)/dt = [-8 +26t]/[2sqrt((2-2t)^2 + (3t)^2)] put t = 1 we get = [-8 +26]/[2sqrt((2-2)^2 + (3)^2)] = [18]/[6] = 3 please rate me.....

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