A reservoir has the shape of a right prism whose parallel bases are isosceles tr

Question

A reservoir has the shape of a right prism whose parallel bases are isosceles triangles, as shown in the ?gure above. It measures 4 m high, 2m wide and 6m long, and it is flled with water. We want to calculate the amount of work required to pump all of its water through the hose standing 3m above the reservoir. (i) Let x be the height in meters measured from the base of the reservoir. The weight of a thin water layer between heights x and x+ delta x is approximately P(x)delta x . What is P(x.)Express the answer using a formula. Recall that the density of water is p=1000kg/m^3 and the acceleration due to gravity on the earth

Explanation / Answer

use tese information this will be helpful for you Formula for Volume of a Triangular Prism We know, The Volume of a Prism = Ah Where, A is area of the base and h is height of the prism. In Triangular Prism, Area of the base (A) = 12 * a * b Volume of Triangular Prism = Ah = 12 * a * b * h where, a = altitude, b = base, h = height. Formula: Volume of Triangular Prism = 12 * a * b * h = 12 abh. Where, a = altitude, b = base, h = height. Example: Find the volume of the triangular prism whose length is 15 cm, altitude 10 cm and base is 11 cm. Solution: Length of the prism (h) = 15 cm Altitude (a) = 10 cm Base (b) = 11 cm Step 1: Area of the base, A = 12 base x height = 12 x 11 x 10 = 55 => A = 55 cm2 . Step 2: Volume of the triangular prism (V) = Ah => V = 55 x 15 = 825 Hence the volume of the triangular prism is 825 cm3 .

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