Iconic memory is a type of memory that holds visual information for about half a
ID: 3216798 • Letter: I
Question
Iconic memory is a type of memory that holds visual information for about half a second (0.5 seconds). To demonstrate this type of memory, participants were shown three rows of four letters for 50 milliseconds. They were then asked to recall as many letters as possible, with a 0-, 0.5-, or 1.0-second delay before responding. Researchers hypothesized that longer delays would result in poorer recall. The number of letters correctly recalled is given in the table. (a). Complete the F-table. (Round your values for MS and F to two decimal places). (b). Compute Tukey's HSD post hoc test and interpret the results. (Assume alpha equal to 0.05.). The critical value is for each pairwise comparison. Which of the comparisons had significant differences? (Select all that apply.) Recall following no delay was significantly different from recall following a one second delay. Recall following a half second delay was significantly different from recall following a one second delay. The null hypothesis of no difference should be retained because none of the pairwise comparisons demonstrate a significant difference. Recall following no delay was significantly different from recall following a half second delay.Explanation / Answer
a)
(b) Tukey's MSD Post Hoc test for pairwaise comparsion . We have to calculate the critical value from the q - value table of number of treatments = 3 and degree of freedomwithin = 15
Q critical = 3.67 [ from q - vlaue table]
we will do test for each pair of values
(1) Delay(0) and Recall(1)
HSDDelay - Recall = (MeanDelay - MenaRecall)/ sqrt (MSW/nh)
MSw is the Mean Square Within, and n is the number in the group or treatment.
MSw = 7.6 and n = 6 => MSW/nh = 6.133/6 = 1.022
HSDDelay - Recall = (8-4)/sqrt(1.022) = 3.96 [ 3.96 > 3.67]
(2) Delay(0) and Before(0.5)
HSDDelay - Before = (MeanDelay - MeaaBefore)/ sqrt (MSW/nh)
MSw is the Mean Square Within, and n is the number in the group or treatment.
MSw = 7.6 and n = 6 => MSW/nh = 6.133/6 = 1.022
HSDDelay - Before = (8-6)/sqrt(1.022) = 1.98 [ 1.98< 3.67]
(3) Recall(1) and Before(0.5)
HSDRecall - Before = (MeanRecall - MeaaBefore)/ sqrt (MSW/nh)
MSw is the Mean Square Within, and n is the number in the group or treatment.
MSw = 7.6 and n = 6 => MSW/nh = 6.13/.6 = 1.022
HSDRecall- Before = (6-4)/sqrt(1.022) = 1.98 [ 1.98< 3.67]
(c) Option 1 is correct where recall after no delay is significantly different from recall following one second delay.
Rest are wrong options.
Anova: Single Factor SUMMARY Groups Count Sum Average Variance Delay (0) 6 48 8 6.4 Before(0.5) 6 36 6 8.8 Recall(1) 6 24 4 3.2 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 48 2 24 3.913043 0.042899 3.68232 Within Groups 92 15 6.133333 Total 140 17Related Questions
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