The graph below depicts the standard normal distribution with a mean of 0 and st
ID: 3217422 • Letter: T
Question
The graph below depicts the standard normal distribution with a mean of 0 and standard deviation of 1. Find the indicated z-score for the shaded area. The shaded area is 0.7599.
– 1.08 (b) 0.71 (c) 1.08 (d) -0.71 (e) -.70
Assume that weight of newborn babies is normally distributed with a mean of 10 lbs and a standard deviation of 2 lbs. Find the probability that a randomly selected newborn baby is greater than 7 lbs.
(a) .0668 (b) .9332 (c) -1.5 (d) .1587
9 Assume that men heights are normally distributed with a mean 69.0 inches and a standard deviation of 2.8 inches. In order to join the U.S. Marine Corp, the requirement is that men should have heights between 64 inches and 80 inches. Find the percentage of men who meet the height requirement.
(a) 68% (b) 93% (c) 96% (d) 85%
10 Refer to question 9 above. If the height requirements for the U.S. Marine Corp are changed so that all men are eligible EXCEPT the shortest 2% and the tallest 5%, what are the new height requirements?
(a) 63 - 74 (b) 68 - 84 (c) 67 - 76 (d) 64 - 77
11 Questions 11– 14 pertain to the following: Assume that weight of newborn babies is normally distributed with a mean of 7 lbs and a standard deviation of 2.5 lbs. Find the probability that a randomly selected newborn baby is greater than 7 lbs.
(a) .2881 (b) .5000 (c) .7881 (d) .2119
12 Refer to question 11 above. Find the probability that a randomly selected newborn baby is less than 11.5 lbs?
(a) .4641 (b). 0359 (c) .9641 (d) .8641
13 Refer to question 11 above. What would be the Z-score of a baby whose weight was 7 lbs?
(a) 0 (b) –1.0 (c) 1.0 (d) 0.5
14 Refer to question 11 above. Find the value of P90. That is, find the weight separating the bottom 90% of babies from the top 10%.
(a) 3.2 lbs (b) 10.2 lbs (c) 4.8 lbs (d) 7.6 lbs
Explanation / Answer
The graph below depicts the standard normal distribution with a mean of 0 and standard deviation of 1. Find the indicated z-score for the shaded area. The shaded area is 0.7599.
Answer : 0.71
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