(19.04) Internet search sites compete for users because they sell advertising sp
ID: 3217965 • Letter: #
Question
(19.04) Internet search sites compete for users because they sell advertising space on their sites and can charge more if they are heavily used. Choose an Internet search attempt at random. Here is the probability distribution for the site the search uses: What is the probability that a search attempt is directed to a site other than Google?
(A) 0.02
(B) 0.32
(C) 0.98
(D) Cannot be determined from the information given
(19.09) Choose at random an American woman between the ages of 15 and 44. Here is the distribution of the number of children the woman has given birth to: (The few women with six or more children are included in the “five children” group.) Describe in words the event P(X 2). What is the probability of this event? (Round your answer to 3 decimal places.) ___________________
(19.14) Many random number generators allow users to specify the range of the random numbers to be produced. Suppose that you specify that the random number Y can take any value between 0 and 5. The density curve of the outcome has a constant height between 0 and 5, and height 0 elsewhere. Find . ___________________
(19.17) The Wechsler Adult Intelligence Scale (WAIS) is a common “IQ test” for adults. The distribution of WAIS scores for persons over 16 years of age is approximately Normal with mean 100 and standard deviation 15. What are the mean and standard deviation of the average WAIS score x for an SRS of 60 people?
(A) Mean = 100, standard deviation = 1.94
(B) Mean = 100, standard deviation = 0.25
(C) Mean = 100, standard deviation = 15
(D) Mean = 13.56, standard deviation = 15
Explanation / Answer
(19.04) (D) Cannot be determined from the information given
19.09)
P(X<=2) means the probability that a randomly selected women of the age between 15 and 44 gives birth to less than or equal to 2 children.
As distribution is not provided not able to find the probability.
19.14)
Here probability of selecting any number is 1/6. This is an example of uniform distribution.
(19.17) (A) Mean = 100, standard deviation = 1.94
Here standard deviation will be the standard error determined by dividing the standard deviation of population by square root of sample size.
SE = 15/sqrt(60) = 1.94
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