7 (12 4 atra In each of these situations, find 6000) when is normal with mean 50

Question

7 (12 4 atra In each of these situations, find 6000) when is normal with mean 5000 and standard deviation 1000 When has 5000 and standard deviation o. mean c) when xis uniformly distribued berween 2000 and 8000. do when K has a triangular between and so0a with mode 4000. Matching Connect (use line sepmerts) each event on the right with the appropriate method ofprobabilay assignment. suubjective, personal (6) getting all four aces in a five card poker hand from awea-shuffled deck classical theoretical equally likely ouscomes, eyes-closad particular loaster oven will work frequentist, eyes open, the newl president ofthe Us will he female

Explanation / Answer

In each of the following, find P(X> 6000)

a) When X is normal with Mean 5000 and standard deviation 1000.

Answer :- Using the empirical rule and the fact that we need here the probability of X exceeding one standard deviation from mean the required probability would be given by,

P(X>6000) = (1-0.68)/2 = 0.17

b) When X has a mean 5000 and standard deviation 0.

Answer :- Since the standard deviation is 0 in this case the probability would be given by,

P(X>6000) = 0

c) When X is uniformly distributed between 2000 and 8000.

Answer :- The required probability would be given by,

P(X> 6000) = (8000-6000)/(8000-2000) = 0.33

d) When X has a triangular distribution between 2000 and 8000 with mode 4000.

Answer :- The required probability would be given by,

P(X> 6000) = (8-6)/(8-4)*(1/6-0) * (8-6) *0.5 = 0.083

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