In an article in CA Magazine, Neil Fitzgerald surveyed Scottish business custome
ID: 3219271 • Letter: I
Question
In an article in CA Magazine, Neil Fitzgerald surveyed Scottish business customers concerning their satisfaction with aspects of their banking relationships. Fitzgerald reports that, in 425 telephone interviews conducted by George Street Research, 71 percent of the respondents gave their banks a high rating for overall satisfaction.
(a) Assuming that the sample is randomly selected, calculate a 99 percent confidence interval for the proportion of all Scottish business customers who give their banks a high rating for overall satisfaction. (Round your answers to 3 decimal places.)
Explanation / Answer
Here n=425 and p=0.71
a. For 99% CI z value is 2.58 as from standard normal table P(-2.58<z<2.58)=0.99
Now Margin of Error=z*SE(p), Where SE(p)=sqrt(p(1-p)/n)
So SE(p)=sqrt(0.71*0.29/425)= 0.022
Hence E=0.022*2.58=0.057
Finlly CI=p+/-E=0.71+/-0.057=(0.653,0.767)
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