A candy company claims that 11% of its plain candies are orange, and a sample of
ID: 3219498 • Letter: A
Question
A candy company claims that 11% of its plain candies are orange, and a sample of 100 such candies is randomly selected. a. Find the mean and standard deviation for the number of orange candies in such groups of 100. mu = sigma = (Round to one decimal place as needed.) b. A random sample of 100 candies contains 10 orange candies. Is this result unusual? Does it seem that the claimed rate of 11% is wrong? A. No, because 10 is within the range of usual values. Thus, the claimed rate of 11% is not necessarily wrong. B. Yes, because 10 is greater than the maximum usual value. Thus, the claimed rate of 11% is not necessarily wrong. C. Yes, because 10 is within the range of usual values. Thus, the claimed rate of 11% is probably wrong. D. Yes, because 10 is below the minimum usual value. Thus, the claimed rate of 11% is probably wrong.Explanation / Answer
ans=
mean = np = 200*.11 = 22
sd = (npq) = (200*.11*.89) = 4.4249
he result is unusual because 10 out of 200 would be 4.42, which is higher than the claim rate of 0.11. 10 is higher than the maximum usual value, so the claimed rate is wrong
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