Asmal company involved in e-commerce is interested in statistics conoeming use o

Question

Asmal company involved in e-commerce is interested in statistics conoeming use of eemal. Apoll found that 38% of a random sample of 1088 adults, who use a computer at their home work or school said they do not send or moeive email. Complete parts a through e. aFind the margin of emor for this polifwe want 9% confidenoe in our estimate of peroentofAmericanadults who do not use e-mail ME-L (Round to three decimal places as needed) b)Explain what that margin of error means O B. The polsters are 96% oonfderteat the margin of emor contains ee tue proportion of aduts who do not use emal. OD. The margin emoris width ofthe confidence interval that contains te true proportion of aduts who do not use e-mal we want be so oonldent, wane margin error belager or smaler? B. Agow confidence intervalleads smaller margin of emor in order to decrease consoence interval must be wider. O c. Agon, confidence interval leads to alarger margin of error In order to increase confdence, the interval must be narrower o D. Aposeersdence interval leads to a maller margin of error in order to deorease oorf dence, the interval must be namower d)Find that margin of error ME-D Round to ree decimal places as needed.) remain the same, smaler margins oferor nvolve greaway or less condence in the intevan O smaller margins of mor wll be he result of ous confident intervals be the result more confident interv click to select your answer 1 2 3

Explanation / Answer

pls check as the digit abovce seems blurry and reply if they are different

p=0.38 and n=1088

hence std error =(p(1-p)/n)1/2 =0.0147

and for 95 % CI. z =1.96

hence margin of error =z|*std error =0.029

b)option C is correct

c) option D is correct

d) for 90% CI, z=1.6449

ME =0.024

e)smaller margin of error will be result of lesser confidence intervals

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