Chapter 11 chi-square test n p Google Chrome Secure https:// Secure h ps://www.
ID: 3219997 • Letter: C
Question
Chapter 11 chi-square test n p Google Chrome Secure https:// Secure h ps://www. mathxl.com /Student/Player Homework aspx? homeworkld 4073145568lq uestionld 18uflushed false&cld; 42927468ucenterwin yes metro Chapter 11 C Statistics Spring 2017 4/10/17 4:48 PM Homework: Homework 11 HW Score: 2.5%, 1 of 40 pts Score 0 of 3 pts 2 of 12 (1 complete Instructor-created question Question Help Conduct the hypothesis test and provide the test statistic, critical vi alue and P-val e, and state the A person randomly selected 100 checks and recorded the cents portions of those checks. The table below lists those cents portions categorized according to the indicated values. Use a 0.05 significance level to test the claim that the four categories are equally likely. The person expected that many checks for whole dollar amounts would result in a disproportionately high frequency for the first category, but do the results support that expectation? Cents portion of check 0-24 25-49 50-74 75-99 Numbe The test statistic is Type an integer or a decimal The P-value is (Round to four decimal places as needed. State the conclusion. Ho. There sufficient evidence to warrant rejection of the claim that the four categories are equally likely. The results to support the expectation that the frequency forthe first category is disproportionately high. Enter your answer in the edit fields and then click Check Answer All parts showing Check Answer Step 2: Decide the type of test n 449 PM 4 4/10/2017 O Ask me anythingExplanation / Answer
Statcrunch Steps:
Stat --> Goodness of Fit --> Chi - square Tes --> Select number column for observed --> Marked All cells in equal proportion for expected --> Compute
The output will be:
closemaximize
Chi-Square goodness-of-fit results:
Observed: Number
Expected: All cells in equal proportion
Hence,
Test statistic = 69.2
p - value = 0
Reject Ho. There is sufficient evidence to warrant rejection of the claim that the four categories are equally likely. The result suggests to support the expectation that the frequency for the first category is dispropotionately high.
N DF Chi-Square P-value 100 3 69.2 <0.0001Related Questions
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