The expected frequency in a chi-square test is found by multiplying the hypothes

Question

The expected frequency in a chi-square test is found by multiplying the hypothesized probability of a cell by the number of pieces of data in the sample.

Question 3 options:

False

In the paper "Color Association of Male and Female Fourth-Grade School Children" (J. Psych., 1988, 383-8), children were asked to indicate what emotion they associated with the color red. The response and the sex of the child are noted and summarized below. The first number in each cell is the count, the second number is the row percent.

Question 8 options:

4.661 .1983

4.661 .3966

4.629 .2011

4.629 .4022

4.629 .1006

False

In the paper "Color Association of Male and Female Fourth-Grade School Children" (J. Psych., 1988, 383-8), children were asked to indicate what emotion they associated with the color red. The response and the sex of the child are noted and summarized below. The first number in each cell is the count, the second number is the row percent.

                Frequency|                Row Pct  |anger   |happy   |love    |pain    |  Total                ---------+--------+--------+--------+--------+                f        |     27 |     19 |     39 |     17 |    102                         |  26.47 |  18.63 |  38.24 |  16.67 |                ---------+--------+--------+--------+--------+                m        |     34 |     12 |     38 |     28 |    112                         |  30.36 |  10.71 |  33.93 |  25.00 |                ---------+--------+--------+--------+--------+                Total          61       31       77       45      214                   Statistic                     DF     Value        Prob                ------------------------------------------------------                Pearson Chi-Square             *     4.629       *****                Likelihood Ratio Chi-Square    *     4.661       *****                Mantel-Haenszel Chi-Square     1     0.307       *****  

  The test statistic and approximate p-value is:   

Question 8 options:

4.661 .1983

4.661 .3966

4.629 .2011

4.629 .4022

4.629 .1006

Explanation / Answer

R=number of rows = 2

C=number of columns=4

df=(R-1)*(C-1) = (2-1)*(4-1)=3

from the given output, test statistic = 4.629

By using excel function =CHIDIST(4.629,3), the p-value = .2011. Therefore, correct option is:

4.629 .2011

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