The Nielsen Company reported that U.S. residents aged 18 to 24 years spend an av

Question

The Nielsen Company reported that U.S. residents aged 18 to 24 years spend an average of 39.4 hours per month using the Internet on a computer. You think this is quite low compared with the amount of time that students at your university spend using the Internet on a computer, and you decide to do a survey to verify this. You collect an SRS of n = 50 students and obtain bar x = 40.2 hours with s = 28.4 hours a) Report the 95% confidence interval for mu, the average number of hours per month that students at your university use the Internet on a computer. Use software to calculation. 95% confidence interval (plusminus 0.001) is from hours to hours (b) Use this interval to test whether the average time for students at your university is different from the average reported by Nielsen. Use the 5% significance level. We cannot reject the average reported by Nielsen We reject the average reported by Nielsen

Explanation / Answer

a) The statistical software output for 95% confidence interval is:

One sample T confidence interval:
: Mean of population

95% confidence interval results:

So,

95% confidence interval is from 32.129 hours to 48.271 hours.

b) Since the interval contains 39.4,

We can not reject the average reported by Nielsen.

Option a is correct.

Mean Sample Mean Std. Err. DF L. Limit U. Limit 40.2 4.0163665 49 32.128809 48.271191

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