In a survey of 617 males ages 18.64, 393 say they have gone to the dentist in th

Question

In a survey of 617 males ages 18.64, 393 say they have gone to the dentist in the past year. Construct 90% and 95% confidence intervals for the population proportion. Interpret results and compare wide of the confidence intervals if use technology to combust the confidence intervals. The 90% confidence interval for the population proportion p is (,). (Round to three decimal places as needed.) The 95% confidence interval for the population proportion p is (,). (Round to three decimal places as needed.) Interpret your results of both confidence intervals. A. With the given confidence, it can be said that the population proportion of males ages 18 64 who say they have gone to the demits in the year past year is between the endpoints of the given condition interval. B. With the given confidence, it can be said that the population proportion of males ages 18.64 who say they have gone to the demits in the past year is between the endpoints of the given condition interval. C. With the given confidence, if can be said that the population proportion of males ages 18 64 who say they have gone to the demits in the past year is between the endpoints of the given condition interval. Which interval is wider? The 90% confidence interval The 95% confidence interval

Explanation / Answer

here estimated proportion phat=393/617 =0.64

hence std error =(p(1-p)/n)1/2 =0.019

for 90% CI,z=1.645

hence confidence interval =phat -/+ z*std error =0.605 ; 0.669

for 95% CI,z=1.96

hence confidence interval =phat -/+ z*std error =0.599 ; 0.675

option B is correct

95% interval is wider

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