The owner of a farmer\'s market was interested in determining how many oranges a

Question

The owner of a farmer's market was interested in determining how many oranges a person buys when they buy oranges. He asked the cashiers over a weekend to count how many oranges a person bought when they bought oranges and record this number for analysis at a later time. The data is given below in the table. The random variable x represents the number of oranges purchased and P(x) represents the probability that a customer will buy x oranges. Determine the variance of the number of oranges purchased by a customer. Round to 2 decimal places

Explanation / Answer

Mean = 1*0.05 + 2*0.19 + 3*0.2 + 4*0.25 + 5*0.12 + 6*0.10 + 7*0 + 8*0.08 + 9*0 + 10*0.01

       = 0.05 + 0.38 + 0.6 + 1 + 0.6 + 0.6 + 0.64 + 0.1

       = 3.97

Variance = S^2

Variance = (3.97-1)^2 *0.05 + (3.97-2)^2 *0.19 * (3.97-3)^2 *0.20 + (3.97-4)^2 *0.25 + (3.97-5)^2 *0.12 + (3.97-6)^2 *0.10 + (3.97-8)^2 *0.08 + (3.97-10)^2 *0.01

      = 0.441045 + 0.737371 + 0.18818 + 0.000225 + 0.127308 + 0.041209 + 1.299272 + 0.363609

      = 3.198219

standard deviation = 1.78835

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.