Many studies have suggested that there is a link between exercise and healthy bo

Question

Many studies have suggested that there is a link between exercise and healthy bones. Exercise stresses the bones and this causes them to get stronger. One study examined the effect of jumping on the bone density of growing rats. There were three treatments: a control with no jumping, a low-jump condition (the jump height was 30 centimeters), and a high-jump condition (60 centimeters). After 8 weeks of 10 jumps per day, 5 days per week, the bone density of the rats (expressed in mg/cm3 ) was measured. Here are the data. data53.dat

(a) Make a table giving the sample size, mean, and standard deviation for each group of rats. Consider whether or not it is reasonable to pool the variances. (Round your answers for x, s, and sx to one decimal place.)

Safari File Edit View History Bookmarks Window Help 96% Sat 5:20 PM a E webassign Topic sax ouiz chegg study Gui... As a researcher y. people sc Discuss a Correlat... Consider A Possib LCS Learning Platf onrecpe... numerator df denominator df 39 2.613 points Previous Answers MIntroStat8 12.E.047. My Notes Ask Your Teache AM Many studies have suggested that there is a link between exercise and healthy bones. Exercise stresses the bones and this causes them to get stronger. One study examined the effect of jumping on the bone density of growing rats. There were three treatments: a control with no jumping, a low-jump condition (the jump height was 30 centimeters), and a high-jump condition (60 centimeters). After 8 weeks of 10 jumps per day, 5 days per week, the bone density of the rats (expressed in mg/cm3) was measured. Here are the data data 53.dat (a) Make a table giving the sample size, mean, and standard deviation for each group of rats. Consider whether or not it is reasonable to pool the variances. (Round your PM answers for X, s, and ST to one decimal place Group Control 10 597.2 31.9 10.1 w jump 1 628.4 617 19.8 16.3 High jump 10 (b) Run the analysis of variance. Report the F statistic with its degrees of freedom and P-value. What do you conclude? (Round your test statistic to two decimal places and your P-value to three decimal places.) Conclusion: There is a statistically significant difference between the three treatment means at the a 05 level Submit Answer Save Prog 313 points Previous Answers MIntroStat8 12.E.504.XP My Notes Ask Your Teache A survey looked at the value of recreational sports on college campuses. One of the questions asked each student to rate the importance of recreational sports to college satisfaction and success. Responses were on a 10-point scale with 1 indicating total lack of importance and 10 indicating very high importance. The following table summarizes these results: Class Mean Score Freshman 722 7.6

Explanation / Answer

Solution:-

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: 1 = 2 = 3

Alternative hypothesis: At-least one of the is not equal.

Formulate an analysis plan. For this analysis, the significance level is 0.05.

Analyze sample data.

F statistics is given by:-

F = 50.001

Fcritical =

The P-value = less than 0.00001

Interpret results. Since the P-value ( almost 0) is less than the significance level (0.05), we have to reject the null hypothesis.

Conclusion:-

Reject H0, There is sufficient evidence for significant differences between the three jumps.

        SS                 df MS F p Between: 4,984.800 2 2,492.400        50.001    0.000 Within: 1,345.860 27 49.847 Total: 6,330.660 29

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