The followings are the questions I have trouble to answer. I am appreciated your

Question

The followings are the questions I have trouble to answer. I am appreciated your help. May I ask if you provide a step by step explanation, please? Thanks!

1.

W hy would you use the Tukey multiple comparison?
(a) To test for normality.
(b) To test for homogeneity of variance.
(c) To test for differences in pairwise means.
(d) To test indep endence of errors.

2.

A randomized blo ck design with 4 treatments and 5 blocks produced
the following sum of squares values: SS(Total) = 1951, SST = 349,
SSE = 188. Find MSB.
(a) MSB = 353.5
(b) MSB = 282.8
(c) MSB 471.3333
(d) MSB 117.8333

3.

An experiment was conducted using a randomized block design with six
(6) treatments and twenty (20) blocks. You are asked to test H0: All
treatment means are equal vs. Ha: At least two treatment means
differ. Find the degrees of freedom for the critical value of F for this
test.
(a) 5 numerator and 19 denominator degrees of freedom.
(b) 19 numerator and 100 denominator.
(c) 5 numerator and 100 denominator degrees of freedom.
(d) 5 numerator and 95 denominator degrees of freedom.

Why would you use the Tukey multiple comparison? (a) To test for normality. (b) To test for homogeneity of variance (c) To test for differences in pairwise means (d) To test independence of errors A randomized block design with 4 treatments and 5 blocks produced the following sum of squares values: SS(Total) J 1951, SST 349 SSE 188. Find MSB. (a) MSB 353.5 (b) MSB 282.8 (c) MSB 471.3333 (d) MSB 117.8333 An experiment was conducted using a randomized block design with six (6) treatments and twenty (20) blocks. You are asked to test Ho: All treatment means are equal vs. Ha: At least two treatment means differ. Find the degrees of freedom for the critical value of F for this test (a) 5 numerator and 19 denominator degrees of freedom. (b) 19 numerator and 100 denominator (c) 5 numerator and 100 denominator degrees of freedom. (d) 5 numerator and 95 denominator degrees of freedom.

Explanation / Answer

1. The answer is C . To test of difference in pairwise means. Hence , it is used to create confidence intervals for all pairwise differences between factor level means

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