a pharmaceutical company wishes to test a new drug with the expectation of lower
ID: 3222240 • Letter: A
Question
a pharmaceutical company wishes to test a new drug with the expectation of lowering cholesterol levels. Ten subjects are randomly selected and pretested. The subjects were placed on the drug for a period of 6 months, after which their cholesterol levels were tested again.
The test results, before and after, are listed below (All units are milligrams per deciliter)
test the company's claim that the drug lowers cholesterol levels using a .01 significance level.
Explanation / Answer
Given that,
population mean(u)=202
sample mean, x =195
standard deviation, s =175
number (n)=250
null, H0: Ud > 0
alternate, H1: Ud < 0
level of significance, = 0.01
from standard normal table,right tailed t /2 =2.821
since our test is right-tailed
reject Ho, if to > 2.821
we use Test Statistic
to= d/ (S/n)
Where
Value of S^2 = [ di^2 – ( di )^2 / n ] / ( n-1 ) )
d = ( Xi-Yi)/n) = 10
We have d = 10
Pooled variance = Calculate value of Sd= S^2 = Sqrt [ 2188-(100^2/10 ] / 9 = 11.489
to = d/ (S/n) = 2.752
Critical Value
The Value of |t | with n-1 = 9 d.f is 2.821
We got |t o| = 2.752 & |t | =2.821
Make Decision
Hence Value of |to | < | t | and Here we Do not Reject Ho
p-value :right tail - Ha : ( p > 2.7524 ) = 0.01119
hence value of p0.01 < 0.01119,here we reject Ho
ANSWERS
---------------
null, H0: Ud > 0
alternate, H1: Ud < 0
test statistic: 2.752
critical value: reject Ho, if to > 2.821
decision: Do not Reject Ho
p-value: 0.01119
we don't have evidence that drug lowers cholesterol levels
X Y X-Y (X-Y)^2 195 180 15 225 225 220 5 25 202 210 -8 64 195 175 20 400 175 170 5 25 250 250 0 0 235 205 30 900 268 250 18 324 190 190 0 0 240 225 15 225 100 2188Related Questions
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