A survey looked at the value of recreational sports on college campuses. One of

Question

A survey looked at the value of recreational sports on college campuses. One of the questions asked each student to rate the importance of recreational sports to college satisfaction and success. Responses were on a 10-point scale with 1 indicating total lack of importance and 10 indicating very high importance. The following table summarizes these results:

Class n Mean score Freshman Sophomore Junior Senior 720 536 593 435 7.6 7.6 7.5 7.3

(a) To compare the mean scores across classes, what are the degrees of freedom for the ANOVA F statistic? numerator df denominator df

(b) The MSG = 11.806. If sp = 2.12, what is the F statistic? (Round your answer to two decimal places.) F =

(c) Give an approximate (from Table E) or exact (from software) P-value. (Enter your answer to four decimal places.)

Explanation / Answer

Groups : Freshman, Sophomore, Junior, Senior

Number of Groups = 4

Number of observations = 720+ 536 +593+ 435 = 2284

Degrees of freedom for group = Number of Groups -1 = 3

Degrees of freedom for total = number of observations -1 = 2284-1=2283

Degrees of freedom for Error = Degrees of freedom for total - Degrees of freedom for group = 2283-3 = 2280

(a) Numerator degrees of freedom = Degrees of freedom for group =3

Denominator degrees of freedom = Degrees of freedom for error = 2280

(b) . F-statistic = MSG /Sp = 11.806/2.12 = 5.57

(c) P-Value =0.000833 . From Excel using the F.DIST.RT(5.57,3,2280) = 0.000833

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.