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https//www.mathxicom/Student/player Testaspx?quizme 18chapter d 108tsectionlda24objectivelda3&studyplanAssignmentld; 968955&viewMode; MATH U102-07 7 17 1 This Question: 1 pt. 4 of 4 This Quiz: 4 pts possib Use technology to help you test the claim about the population ean at the gyenlevelofsignfcance usng the giren sample statstics Assume the population is normally distibuted cam vs 1300 a 003 e 200 B2 sample staristics 1319.33 n 275 vdernfy the null and anernative hypotheses aoose the comect answer below A. Ho ws1300 He 1300 1300 ar C. Ho v 131933 O D. Ho Rs 131933 H. Fs 131933 He p 131933 Ho 1300 OR H 1319 33 H. 1300 H, 1319 30 Calculate the standalazed not statste the standardized tatt tatistik Round to two dec mal places as needed Round to decinal places needed Dutk to select roun answer si

Explanation / Answer

Given that,
population mean(u)=1300
standard deviation, =200.82
sample mean, x =1319.33
number (n)=275
null, Ho: <=1300
alternate, H1: >1300
level of significance, = 0.03
from standard normal table,right tailed z /2 =1.881
since our test is right-tailed
reject Ho, if zo > 1.881
we use test statistic (z) = x-u/(s.d/sqrt(n))
zo = 1319.33-1300/(200.82/sqrt(275)
zo = 1.59621
| zo | = 1.59621
critical value
the value of |z | at los 3% is 1.881
we got |zo| =1.59621 & | z | = 1.881
make decision
hence value of |zo | < | z | and here we do not reject Ho
p-value : right tail - ha : ( p > 1.59621 ) = 0.05522
hence value of p0.03 < 0.05522, here we do not reject Ho
ANSWERS
---------------
null, Ho: <=1300
alternate, H1: >1300
test statistic: 1.59621
critical value: 1.881
decision: do not reject Ho
p-value: 0.05522

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