A classic experiment by Dutton & Aron (1974) examined men\'s attraction to a fem

Question

A classic experiment by Dutton & Aron (1974) examined men's attraction to a female they met in either one of two conditions: on a high unstable, shaky bridge or on a low sturdy bridge. Later, they rated the attractiveness of the woman. The following data is a generated replica of this study. Attractiveness was rated as 1-10 with 10 being very attractive. The researchers want to evaluate how the independent variable (bridge height) affects attractiveness ratings. More specifically, they predict that those men in the higher bridge condition will rate the woman as being more attractive. a.) State your null and alternative hypotheses. b.) What are your degrees of freedom and critical value(s) given an alpha = .05 level? c.) What is the estimated standard error? d.) Calculate your test statistic. e.) Given the alpha level of alpha = .05, what would the researchers conclude about bridge height and attractiveness ratings? Write a conclusionary statement and be sure report your results as it would appear in an APA compliant manuscript (e.g. t(df) = t_obs, p

Explanation / Answer

(a) Null Hypothesis : H0: There is no difference between mean rating for women for higher bridge and mean rating for women for lower bridge.

Alternative Hypothesis : Ha : There is higher mean average rating for women for higher bridge condition than mean rating for women for lower bridge.

(b) Degrees of freedom = (n1 - 1) + (n2 -1) = (17-1) + (22 -1) = 37

critical values and significance level alpha = 0.05 => tcritical = 1.6870 as a right tailed test

(c) Estimated Standard error : Here equal population variance has been assumed

Pooled Standard Deviation sp = Sqrt [ (n1 -1) s12 + (n2-1)s22 / (n1 + n2-2) ]

= Sqrt [ SS1+ SS2/ (n1 + n2-2) ]

= Sqrt [ (201 + 154)/ 37] = 3.0975

and Estimated Standard Error SE0= sp* sqrt [ 1/n1+ 1/n2] = 3.0975 * sqrt[ 1/ 17 + 1/22] = 1.000

(d) Test Statistic

t = (M1- M2)/ SE0= (6.82 - 4.57) /1 = 2.25

(e) for alpha = 0..05 significance level, we find t > tcriticalso we can reject the null hypothesis and can conclude that there is increase rating in mean women attractiveness ratings in higher bridge height in comparison to lower bridge height.

The P-Value is 0.015242.

The result is significant at p < .05.

High Bridge Low Bridge n1 = 17 n2 = 22 SS1= 201 SS2 = 154 M1= 6.82 M2 = 4.57

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.