In a survey of 1000 people, the following question was asked: How much emergency

Question

In a survey of 1000 people, the following question was asked: How much emergency living expense savings do you have? Answers were expressed in die number of months the person could live on savings. The following results were obtained: Let X denote the random variable that Hikes on the values 1, 2, 3, and 4. corresponding to the groups given in the table. a. Find the probability distribution associated with these data. b. If a respondent in the survey is chosen at random, what is the probability that he or she said that they had 6 or fewer months' worth of emergency living expense savings?

Explanation / Answer

Part-a

Probability distribution is as follows:

PArt-b

P(6 or Fewer than 6 months)=1-P(More than 6)

=1-0.29

=0.71

Probability Distribution X Time Number Probability p=Number/1000 1 Less than 3 480 0.48 2 3-6 200 0.2 3 More than 6 290 0.29 4 No answer 30 0.03 Total 1000 1

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