In a random sample of males, it was found that 21 write with their left hands an

Question

In a random sample of males, it was found that 21 write with their left hands and 213 do not. In a random sample of females, it was found that 63 write with their left hands and 440 do not. Use a 0.01 significance level to test the claim that the rate of left-handedness among males is less than that among females.
**Im having trouble identifying the test statistic z. Using my TI-84, I entered STAT -> TESTS -> 6:2-PropZTest... x1= 21, n1= 213, x2= 63, n2= 440, p1= <p2 -> Calculate -> ENTER and I get z= -1.5955 but MyStatLab says it's wrong and said that -1.41 is the correct answer? In a random sample of males, it was found that 21 write with their left hands and 213 do not. In a random sample of females, it was found that 63 write with their left hands and 440 do not. Use a 0.01 significance level to test the claim that the rate of left-handedness among males is less than that among females.
**Im having trouble identifying the test statistic z. Using my TI-84, I entered STAT -> TESTS -> 6:2-PropZTest... x1= 21, n1= 213, x2= 63, n2= 440, p1= <p2 -> Calculate -> ENTER and I get z= -1.5955 but MyStatLab says it's wrong and said that -1.41 is the correct answer?
**Im having trouble identifying the test statistic z. Using my TI-84, I entered STAT -> TESTS -> 6:2-PropZTest... x1= 21, n1= 213, x2= 63, n2= 440, p1= <p2 -> Calculate -> ENTER and I get z= -1.5955 but MyStatLab says it's wrong and said that -1.41 is the correct answer?

Explanation / Answer

In your calculator You entered x1 =21 which is correct but for n1 value you have to enter total number of population

In the first case, that is in male there are 21+213 = 234 total males.

so n1 = 234.

Similarly x2 = 63 and n2 = 63 + 440 = 503

So now You can enter values as

x1 = 21 , n1 = 234

x2 = 63, n2 = 503

with these values calculate z score in your TI-84 calculator, you will get answer as -1.4119 or -1.41 .

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