A study revealed that the 30-day readmission rate was 34.6 percent for 321 patie
ID: 3223741 • Letter: A
Question
A study revealed that the 30-day readmission rate was 34.6 percent for 321 patients who received after-hospital care instructions (e.g., how to take their medications) compared to a readmission rate of 43.9 percent for 321 patients who did not receive such information.
Find the exact p-value for the test. (Round your answer to 4 decimal places.)
We (Click to select)cancannot conclude that the admissions rate was lower for those who received the information.
A study revealed that the 30-day readmission rate was 34.6 percent for 321 patients who received after-hospital care instructions (e.g., how to take their medications) compared to a readmission rate of 43.9 percent for 321 patients who did not receive such information.
(a)Choose the appropriate hypotheses to see whether the admissions rate was lower for those that received the information. Assume 1 is the proportion of those that received the information and 2 is the proportion of those that did not.
a. H0: 1 2 0 vs. H1: 1 2 < 0 b. H0: 1 2 = 0 vs. H1: 1 2 0c. H0: 1 2 0 vs. H1: 1 2 > 0
(b)Find the exact p-value for the test. (Round your answer to 4 decimal places.)
(c-1) What is your conclusion at = 0.01?We (Click to select)cancannot conclude that the admissions rate was lower for those who received the information.
(c-2) What is your conclusion at = 0.02? We (Click to select)cancannot conclude that the admissions rate was lower for those who received the information.Explanation / Answer
Given that,
sample one, x1 =111.066, n1 =321, p1= x1/n1=0.346
sample two, x2 =140.919, n2 =321, p2= x2/n2=0.439
null, Ho: p1 - p2 0
alternate, H1: p1 - p2 = 0
level of significance, = 0.01
from standard normal table,left tailed z /2 =
since our test is left-tailed
reject Ho, if zo < -2.326
we use test statistic (z) = (p1-p2)/(p^q^(1/n1+1/n2))
zo =(0.346-0.439)/sqrt((0.393*0.608(1/321+1/321))
zo =-2.413
| zo | =2.413
critical value
the value of |z | at los 0.01% is 2.326
we got |zo| =2.413 & | z | =2.326
make decision at 0.01
hence value of | zo | > | z | and here we reject Ho
p-value: left tail - Ha : ( p < -2.4128 ) = 0.00791
hence value of p0.01 > 0.00791,here we reject Ho
ANSWERS
---------------
null, Ho: p1 - p2 0
alternate, H1: p1 - p2 < 0
test statistic: -2.413
critical value: -2.326
decision: reject Ho
p-value: 0.00791
he admissions rate was lower for those who received the information
make decision at 0.02
critical value
the value of |z | at los 0.02% is 2.054
we got |zo| =2.413 & | z | =2.054
make decision
hence value of | zo | > | z | and here we reject Ho
p-value: left tail - Ha : ( p < -2.4128 ) = 0.00791
hence value of p0.02 > 0.00791,here we reject Ho
ANSWERS
---------------
test statistic: -2.413
critical value: -2.054
decision: reject Ho
p-value: 0.00791
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