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Favorites Help C For N Nett... o Since the p value 005, there is signitcant evid

ID: 3223953 • Letter: F

Question

Favorites Help C For N Nett... o Since the p value 005, there is signitcant evidenoe that melanomas in men are not evenly spread over all four body locators senoking remains more common in much of Europe than in the United saates. the united saates, there is astrong nelationship between dation and smoking: weaedu education and smoking status (nonsmoker, former smoker, moderate are less likely to smoke. Does a similar relationship hold in France? Here is a twoway randemsample men who visited a hearth center for a routine deckaw "rare ng" heavy smoker) of a sample of 455 French men aged 20 to 60 years The subjects are a consider them an SRS of men from their region of France. 26 35 15 althree leveludedueason. p between these variables. Thata, the distrbution of smoking the same for table expected oaures Rnd the The null hypothesis states that there is no two way (a) Find the expected counts for smoking status among men with a university education. This one new of ehe each total for the observed counts. verify that it agrees count and a whole number for the total. use two decimals for the O Ask me

Explanation / Answer

(a) The observed counts for men with university education is

Expected frequency for the ith row/jth column, Eij = Ti * Tj/ N

Ti = total in the ith row

Tj = total in the jth column

N = table grand total.

Grand total = 455
Total number of men with university education = 129
Total number of Non-smoker = 148
Total number of Former smoker = 121
Total number of Moderate smoker = 101
Total number of Heavy smoker = 85

(b) Looking at the obeserved and expected count, the correct option are
The heavy-smoker count is less than expected
The nonsmoker count is higher than expected.

Education NonSmoker Former Moderate Heavy Total University 53 26 35 15 129 Expected 129*148/455 = 41.96 129*121/455= 34.31 129*101/455= 28.63 129*85/455= 24.10 129