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In a survey of 4004 adults. 718 say they have seen a ghost. Construct a 99% conf

ID: 3224035 • Letter: I

Question

In a survey of 4004 adults. 718 say they have seen a ghost. Construct a 99% confidence interval for the population proportion Interpret the results A 99% confidence interval for the population proportion is ((Round to three decimal places as needed.) Interpret your results Choose the correct answer below A. With 99% probability the population proportion of adults who say they have not seen a ghost is between the endpoints of the given confidence interval B. The endpoints of the given confidence interval show that 99% of adults have seen a ghost C. With 99% confidence, it can be said that the sample proportion of adults who say they have seen a ghost is between the endpoints of the given confidence interval D. With 99% confidence, it can be said that the population proportion of adults who say they have seen a ghost is between the endpoints of the given confidence interval

Explanation / Answer

here estimate proportion p=718/4004=0.179

std error =(p(1-p)/n)1/2 =0.0061

for 99% CI, z=2.5758

hence confidence interval =estimated proportion -/+ z*std error =0.1637 ; 0.1949

option D is correct

please reply for further clarity

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