Drabkin\'s reagent, containing 12 mM NaHCO 3 , 0.77 mM KCN and 0.88 mM K 3 Fe(CN
ID: 3224399 • Letter: D
Question
Drabkin's reagent, containing 12 mM NaHCO3, 0.77 mM KCN and 0.88 mM K3Fe(CN)6, is used to assay the concentration of hemoglobin ([Hb]) in whole blood. The light absorbance at 540 nm (ABS540) is proportional to the concentration of cyanmethemoglobin ([CyanmetHb]), which is in turn directly proportional to [Hb]. Preparation of a new Drabkin's solution requires the running of a "standard curve" to determine the relationship between ABS540 and known concentrations of [Hb]. The data in the table below are ABS540 in triplicate measures of standard samples containing standard [Hb] concentrations of 0, 3, 6, 9, 12, 15 and 18 grams·100 ml blood-1. 20 ml of well mixed whole blood is suspended in 5 ml of Drabkins. The erythrocytes are hemolyzed with the resulting formation of a cyanmethemoglobin compound that optimally absorbs light at a wave length of 540 nm. An exercise physiologist plans to use for Hb determination (prediction) in screening female distance runners for possible anemia ([Hb] < 12 g·100 ml-1) in females.
Part A) What statistical procedure is used to predict or determine the [Hb] in known blood samples based on the strong association between [Hb] and ABS540?
a. dependent t-test
b. multiple linear regression
c. simple linear regression
d. repeated measures ANOVA
e. Pearson product moment correlation coefficient
Part B) Select the correct statement.
a. The coefficient of determination is the proportion of error variance.
b. 1-r2 is the common or shared variance.
c. 99.9% of the variance in [Hb] is explained by ABS540 nm in this the standard curve for this cyanmethemoglobin solution
Part C) Select the correct option below regarding hemoglobin concentration [Hb] and optical density at 540 nm (OD).
a. [Hb] = -8.732 + (0.030·ABS540)
b. [Hb] = 0.069 + (33.521·ABS540)
c. [Hb] = -0.002 + (8.734·ABS540)
d. [Hb] = 11.398 + (9.00·ABS540)
e. There is insufficient information to determine [Hb] from ABS540.
Y IHbl [CyanmetHbl X-Absorbance at 540 Hb? ABS540 CyanmetHb g 100 ml mg 100 ml nm (ABS540) ABS540 12.0 9.0 0.0081 6 239 0.175 36.0 00306 1.0500 9 35.9 0.265 81.0 0.0702 2.3850 12 47.8 0.350 144.00 0.1225 4.2000 59.8 0.445 225.0 0.1980 324.0 0.2916 9.7200 633 1.865 819.01 244.3000 0.7211 9.0 0.266 R 6.4830741 0.193 0.99983Explanation / Answer
Answer:
Part A) What statistical procedure is used to predict or determine the [Hb] in known blood samples based on the strong association between [Hb] and ABS540?
a. dependent t-test
b. multiple linear regression
Answer: c. simple linear regression
d. repeated measures ANOVA
e. Pearson product moment correlation coefficient
Part B) Select the correct statement.
a. The coefficient of determination is the proportion of error variance.
b. 1-r2 is the common or shared variance.
Answer: c. 99.9% of the variance in [Hb] is explained by ABS540 nm in this the standard curve for this cyanmethemoglobin solution
Part C) Select the correct option below regarding hemoglobin concentration [Hb] and optical density at 540 nm (OD).
a. [Hb] = -8.732 + (0.030·ABS540)
Answer: b. [Hb] = 0.069 + (33.521·ABS540)
c. [Hb] = -0.002 + (8.734·ABS540)
d. [Hb] = 11.398 + (9.00·ABS540)
e. There is insufficient information to determine [Hb] from ABS540.
Regression Analysis
r²
1.000
n
7
r
1.000
k
1
Std. Error
0.132
Dep. Var.
Hb
ANOVA table
Source
SS
df
MS
F
p-value
Regression
251.9127
1
251.9127
14425.34
7.59E-10
Residual
0.0873
5
0.0175
Total
252.0000
6
Regression output
confidence interval
variables
coefficients
std. error
t (df=5)
p-value
95% lower
95% upper
Intercept
0.0690
0.0896
0.770
.4762
-0.1613
0.2992
ABS540
33.5213
0.2791
120.106
7.59E-10
32.8039
34.2388
Regression Analysis
r²
1.000
n
7
r
1.000
k
1
Std. Error
0.132
Dep. Var.
Hb
ANOVA table
Source
SS
df
MS
F
p-value
Regression
251.9127
1
251.9127
14425.34
7.59E-10
Residual
0.0873
5
0.0175
Total
252.0000
6
Regression output
confidence interval
variables
coefficients
std. error
t (df=5)
p-value
95% lower
95% upper
Intercept
0.0690
0.0896
0.770
.4762
-0.1613
0.2992
ABS540
33.5213
0.2791
120.106
7.59E-10
32.8039
34.2388
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