Assume that a procedure yields a binomial with n trials and the probability of s

Question

Assume that a procedure yields a binomial with n trials and the probability of success for one trials is p Use the given values of n and p to find the mean mu and standard deviation sigma. Also, use the range rule of thumb to find the minimum usual value and the maximum usual value mu - 2 sigma and the maximum usual value mu + 2 sigma. n =240, p = 0.7 mu = sigma = (Round to one decimal place as needed.) mu - 2 sigma = (Round to one decimal place as needed.) mu + 2 sigma = (Round to one decimal place as needed.) Enter your answer in each of the answer boxes.

Explanation / Answer

n = 240

p = 0.7

= n * p = 240 * 0.7 = 168

= sqrt [ n * p * (1-p)] = sqrt [ 240 * 0.7 * 0.3 ] = 7.1

- 2 = 168 - 2 * 7.1 = 153.8

+ 2 = 168 + 2 * 7.1 = 182.2

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