Problem 2. Please show steps/ equations used. Thanks. https:// canvas ou.edu cou
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Problem 2. Please show steps/ equations used. Thanks.
https:// canvas ou.edu courses/38526/files/folder/Assignments?preview 4681032 flights, and Gamma Airlines had 11 exceedences out of 198 flights. Conclude with 90% confidence if StaleAir has a higher proportion of exceedences. Use the p-value approach. Problem 2 Measuring the actual dimensions of a manufactured part is a classical problem in many different disciplines, particularly for quality engineers. A quality engineer is measuring the thickness of nickel plates for use in a nickel-hydrogen battery. By the way the plate is made, she can consistently identify specific locations on each plate. That is, location A is in the same spot on each plate, and location B is in the same spot on each plate. She believes that measuring thickness at location A results in a consistently thicker measure than at location B. She measured thickness, in mm, at locations A and B on 10 particular plates. Location A 31.10 31.10 30.90 30.80 32.20 30.40 29.65 29.85 29.85 30.65 Location B 29.75 29.75 30.15 30.80 30.20 30.40 30.35 29.75 29.15 30.50 a. Conduct an appropriate hypothesis test with 95% confidence. Use the critical value approach. b. Produce a 99% confidence interval for the true mean difference in the thicknesses. Problem 3 The manager of a fast food restaurant believed that customer service times were not consistent throughout the day. As such, she collected service time data for customers who were served n 9.00a and 10.00a on 047 PM a 6 Type here to search 4/24/2017Explanation / Answer
Part-a
Null hypothesis H0: µd=0
Alternative hypothesis Ha: µd>0
Here µd is the true mean of the difference in the thickness A-B.
From following calculations, mean xbard=0.57, standard deviation sd=081, sample size n=10
Degree of freedom =n-1=10-1=9
Level of significance alpha=0.05
Right tailed Critical t =1.833
Test statistics t=(xbard-0)/(sd/sqrt(n)) = (0.57-0)/(0.81/sqrt(10)) =2.23
As calculated t>1.833,we reject the null hypothesis and conclude that location A results in consistently thicker measure than location B.
Location A
Location B
Difference=A-B
31.10
29.75
1.35
31.10
29.75
1.35
30.90
30.15
0.75
30.80
30.80
0.00
32.20
30.20
2.00
30.40
30.40
0.00
29.65
30.35
-0.70
29.85
29.75
0.10
29.85
29.15
0.70
30.65
30.50
0.15
Total
5.70
Mean
0.57
SD
0.81
Part-B
For 99% confidence interval critical t=3.250
So 99% confidence interval =xbard±t*(sd/sqrt(n))
= 0.57±3.250*(0.81/sqrt(10))
=(-0.2625 1.4025)
Location A
Location B
Difference=A-B
31.10
29.75
1.35
31.10
29.75
1.35
30.90
30.15
0.75
30.80
30.80
0.00
32.20
30.20
2.00
30.40
30.40
0.00
29.65
30.35
-0.70
29.85
29.75
0.10
29.85
29.15
0.70
30.65
30.50
0.15
Total
5.70
Mean
0.57
SD
0.81
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