Find the value of the test statistic z using z = p - p/Squareroot pq/n. A claim

Question

Find the value of the test statistic z using z = p - p/Squareroot pq/n. A claim is made that the proportion of children who play sports is less than 0.5, and the sample statistics include n = 1316 subjects with 30% saying that they play a sport. A) 29.62 B) 14.51 C) -29.62 D) -14.51 Use the given degree of confidence and sample data to construct confidence interval for the population mean mu. Assume that the population has a normal distribution. Thirty randomly selected students took the calculus final. If the sample mean was 87 and the sample standard deviation was 110, construct a 99 percent confidence interval for the mean score of all students. A) 89.53

Explanation / Answer

Q-4

Z=(phat-p)/sqrt(p*(1-p)/n)

=(0.30-0.5)/sqrt(0.5*(1-0.5)/1316)

=-14.51

Q-5

Sample size n=30

Degree of freedom =n-1=30-1=29

Critical t at 99% confidence tc=2.756

So99%confidence interval = Mean±tc*s/sqrt(n)

=87±2.756*11/sqrt(30)

=(81.47                 92.53)

So, part-D is asnwer

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