Lcs Learning platform x Topic Eight Homework x C statistics and probability x a

Question

Lcs Learning platform x Topic Eight Homework x C statistics and probability x a C www.webassign.net/web/Student/Assignment-Responses/last?dep 15352565-Q7 Section 17 10. O -2 points PrivteraStats2 17.E 031 My Notes Ask Your Teacher Altamura, Dell'Osso, Vismara, and Mundo (2008) measured the relationship between gender and duration of untreated illness (DU among a sample of those suffering from major depressive disorder (MDD). The following table lists the observed frequencies from this study. Duration Untreated Illness DUI s 12 DUI 12 Months onth Women 75 38 113 Compute a chi-square test for independence at a 0.05 level of significance. (Round your answer to two decimal places.) Decide whether to retain or reject the null hypothesis. O Retain the null hypothesis. O Reject the null hypothesis. You may need to use the appropriate table in Appendix B to answer this question. Additional Materials Section 17 a 3 24 PM 4) 4/26/2017 Type here to search

Explanation / Answer

DF = (r - 1) * (c - 1) = (2 - 1) * (2 - 1) = 1

Er,c = (nr * nc) / n
E1,1 = (25 * 75) / 113 = 16.592
E1,2 = (25 * 38) / 113 = 8.407
E2,1 = (88 * 75) / 113= 58.407
E2,2 = (88 * 38) / 113 = 29.593

2 = [ (Or,c - Er,c)2 / Er,c ]

^2 = (20 - 16.592)^2/16.592 + (5 - 8.407)^2/8.407
+ (55 - 58.407)^2/58.407 + (33 - 29.593)^2/29.593

^2 = 2.6716

p value is calculated using x^2 = 2.6716 , df = 1
p value = 0.102153.

Retain the null hypothesis
because p value is greater tahn 0.05 significance level

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.