Silicone implant augmentation rhinoplasty is used to correct congenital nose def
ID: 3228711 • Letter: S
Question
Silicone implant augmentation rhinoplasty is used to correct congenital nose deformities. The success of the procedure depends on various biomechanical properties of the human nasal periosteum and fascia. An article reported that for a sample of 11 (newly deceased) adults, the mean failure strain (%) was 26.0, and the standard deviation was 3.1. (a) Assuming a normal distribution for failure strain, estimate true average strain in a way that conveys information about precision and reliability. (Use a 95% confidence interval. Round your answers to two decimal places.) b) Predict the strain for a single adult in a way that conveys information about precision and reliability. (use a 95% prediction interval. Round your answers to two decimal places.) How does the prediction compare to the estimate calculated in part (a)? The prediction interval is much wider than the confidence interval in part (a). The prediction interval is much narrower than the confidence interval in part (a). You may need to use the appropriate table in the Appendix of Tables to answer this question.Explanation / Answer
A.
Calculating the population mean strain from the sample data
Sample mean x = 26
Standard error of the sample = sqrt(p*(1-p)
Sample size n = 11
Population mean = 26 +(-) 3.1/sqrt(11) = 26 +- t*0.93
Using a confidence interval of 95%, t = 2.069 for n-1 (= 10) degrees of freedom
Population mean = 26 +- 2.069*0.93 => 24.07 % to 27.92 %
B
Predicting the strain for 1 person
It will have the same mean and standard deviation equal to population standard deviation.
Mean = 26
Standard deviation (approx) = 3.1
Predicted mean of strain = 26 + /- 2*3.1 = 19.8 % to 32.2 %
C
The prediction interval is much wider than the confidence interval in part A (second choice)
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