A manufacturer wished to compare the effectiveness of four methods of treating r
ID: 3229209 • Letter: A
Question
A manufacturer wished to compare the effectiveness of four methods of treating raw fabric to render it water repellant. Six types of fabric were used in the operation. A specimen of each type was divided into fourths, and each fourth was randomly assigned to one of the four methods. After treatment, each item was tested for water-repellency wand scored either 0 if unsatisfactory or 1 if satisfactory. The results are shown below.
Can you conclude (using Cochran’s test) that these data provide sufficient evidence to indicate a difference among the methods?
Data:
2
Method Fabric A B C D 1 1 1 0 02
1 1 0 1 3 1 0 0 0 4 1 1 1 0 5 1 1 0 1 6 1 1 0 1Explanation / Answer
Cochran's Q test is
H0: The methods are equally effective.
Ha: There is a difference in effectiveness among methods.
Step :1 Arrange the data in proper row and column. It is already arranged
Step :2 Compute the sum of each column and row
Sum for each column
G1 = 6 ; G2 = 3; G3 = 1; G4 = 3
sum of G = G* = 6 + 3 + 1 + 3 = 13
G*2 = 62 +32 +12 +32 = 55
Compute the sum of L *= L1 + L2 + L3 + L4 + L5 + L6 = (2+ 3 + 1+ 3 +3 +3)=15
sum of L*2 = 41
Step : 3 Number of condition k = 4
Step : 4 Cochran Statistic
Q = (k-1)[ k x G2 * - (G*)2 ] / ( k x L* - L*2]
Q = (4-1) [ 4 * 55 - 132] / (4 * 15 - 41) = 3 * 51/ 19 = 8.053
Step :5 see chi- square table for critica value for dF = 3 and alpha = 0.05
X2critical = 7,82
Step : 6
For the example data, we would decide to reject the null hypothesis, because the obtained Q value of 8.053 is larger than the critical Chi-square value of 7.82. and we can conclude that these data provide sufficient evidence to indicate a difference among the methods.
Method Fabric A B C D Total(Li) Li^2 1 1 1 0 0 2 4 2 1 1 0 1 3 9 3 1 0 0 0 1 1 4 1 1 1 0 3 9 5 1 1 0 1 3 9 6 1 1 0 1 3 9 Total Gi 6 5 1 3Related Questions
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