An aircraft seem require 30 rivets. The seam will have to be reworked if 3 or mo

Question

An aircraft seem require 30 rivets. The seam will have to be reworked if 3 or more of these rivets are defective. Suppose rivets are defective independently of one another, each with the same probability Let p denote the probability of a rivet being defective What should the value of p be to ensure that only approximately 8% of the seams need reworking? That means P(a seam needing rework) is 0.08] Answer here----> P(a seam needing rework) 1-P(0 rivets defective out of 30)-P(1 rivet defective out of 30) -P(2 rivets defective out of 30) 0.03386 let p pla seam needing rework) 0.07999938 when p 0.033857, 8% of the seams will need rework

Explanation / Answer

THis can be done using a quadratic equation solver. Get the Solver Add-in for excel to type the equation and solve it.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.