Use scholarly writing and proper APA format to briefly discuss in narrative form
ID: 3229253 • Letter: U
Question
Use scholarly writing and proper APA format to briefly discuss in narrative form, the results of the t-test and the correlation.
Correlations
Years_of_Experience
Confidence_Scores
Years_of_Experience
Pearson Correlation
1
.152
Sig. (2-tailed)
.521
N
20
20
Confidence_Scores
Pearson Correlation
.152
1
Sig. (2-tailed)
.521
N
20
20
Independent Samples Test
Levene's Test for Equality of Variances
t-test for Equality of Means
F
Sig.
t
df
Sig. (2-tailed)
Mean Difference
Std. Error Difference
95% Confidence Interval of the Difference
Lower
Upper
Years_of_Experience
Equal variances assumed
1.989
.176
.483
18
.635
2.10000
4.35086
-7.04082
11.24082
Equal variances not assumed
.483
14.584
.636
2.10000
4.35086
-7.19672
11.39672
Confidence_Scores
Equal variances assumed
.268
.611
-1.006
18
.328
-4.30000
4.27304
-13.27733
4.67733
Equal variances not assumed
-1.006
13.694
.332
-4.30000
4.27304
-13.48402
4.88402
Correlations
Years_of_Experience
Confidence_Scores
Years_of_Experience
Pearson Correlation
1
.152
Sig. (2-tailed)
.521
N
20
20
Confidence_Scores
Pearson Correlation
.152
1
Sig. (2-tailed)
.521
N
20
20
Explanation / Answer
From the correlation results, it can be seen that
p-value is the Sig. (2-tailed) = 0.521
As the p-value is not small, the correlation is not significant.
From the t-test results for Years_of_Experience, with Equal variances assumed,
p-value is the Sig. (2-tailed) = 0.635
Since the p-value is not small (high), there is no difference in means and you can’t reject the null hypothesis.
This is true, also as the 95% confidence interval [-7.04082 , 11.24082] contains value '0'.
From the t-test results for Years_of_Experience, with Equal variances not assumed,
p-value is the Sig. (2-tailed) = 0.636
Since the p-value is not small (high), there is no difference in means and you can’t reject the null hypothesis.
This is true, also as the 95% confidence interval [-7.19672 , 11.39672] contains value '0'.
From the t-test results for Confidence_Scores, with Equal variances assumed,
p-value is the Sig. (2-tailed) = 0.328
Since the p-value is not small (high), there is no difference in means and you can’t reject the null hypothesis.
This is true, also as the 95% confidence interval [-13.27733 , 4.67733] contains value '0'.
From the t-test results for Confidence_Scores, with Equal variances not assumed,
p-value is the Sig. (2-tailed) = 0.332
Since the p-value is not small (high), there is no difference in means and you can’t reject the null hypothesis.
This is true, also as the 95% confidence interval [-13.48402 , 4.88402] contains value '0'.
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