ntage confidence ght of 88.0 of usin a ent that interprets int wel 3. interval k
ID: 3229907 • Letter: N
Question
ntage confidence ght of 88.0 of usin a ent that interprets int wel 3. interval kg? y is terminology of prediction instead that of used interval simply the prediction interval inste the linear of Determination Using the heights and weights describ What practical information ris 0.356. the value of the coefficient of determina 4. Standard does the coefficient of provide? their Error of Estimate A sample of 12 different statistics textbooks obtained is what weights are measured in kilograms and in pounds. Using 12 paired weights (kg the is the value of s For a textbook that weighs 4.5 lb, the predicted weightin grams is 2.04 kg. What is 95% ction interval? the Interpreting the coefficient of Determination. In Exercises 5-8, use the value r of the total variation the coefficient of determination and the percen variables from the that can be explained by the linear relationship between the tw Appendix B data sets. 5 r 0.933 (x ght of male y waist size of male 6. r 0.963 (x chest size of a bear, y ght a bear) of 7. -0.793 (x ght of a car, y highway fuel consumption) 0.751 (x ght of discarded plastic, y household size interpreting a computer Display. In Exercises 9-12, refer to the Minitab diplay obtained by using the paired data consisting offoot lengths (em) and beights of people listed in Data Set 2 ofAppendix B. (Unlike the exam in this section, the ples data, Minitab was also given a length of 29.0 cm to be used forpredictingbeight foot MINITAB The regression equation is Foot Length 4.29 Predictor Coef SE coef T P natant 64.13 11.49 5.58 0.000 Foot Length 0.4460 9.62 0.000 5.50571 70.14 R-sq (adj Predicted values tor Nev observations PI Fit SE rit 954 CI (176.896, 188.572 1.710 (105.095. 192.0491 New 1 alues or Predictor a for New abservations New obaExplanation / Answer
Answer:
The correlation coefficient between the two variables chest size of a bear and weight of a bear is given as r = 0.963. For the given scenario, the dependent variable y is given as the weight of the bear while independent variable x is given as chest size of a bear.
The coefficient of determination or the value of R square is given as below:
Coefficient of determination = R square = r^2 = r*r = 0.963*0.963 = 0.927369
We get the coefficient of determination or the value of R square as 0.9274, which means about 92.74% of the total variation in the dependent variable weight of the bear is explained by the linear relationship or independent variable chest size of a bear.
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