A 2010 survey asked 827 randomly sampled registered voters in California if they

Question

A 2010 survey asked 827 randomly sampled registered voters in California if they support or oppose coastal drilling for oil and natural gas. The results of the responses are summarized in the contigency table below.

You perform a chi-squared test for independence on these data to determine if there is an association between having a college degree and one's view on drilling for oil and natural gas. You find that the chi-squared statistic is 11.46 for these data. What is the p-value for this hypothesis test?

A 2010 survey asked 827 randomly sampled registered voters in California if they support or oppose coastal drilling for oil and natural gas The results of the responses are summarized in the contigency table below. College degree Yes No Support 154 132 view on drilling Oppose 180 126 Don't know 104 131 You perform a chi-squared test for independence on these data to determine if there is an association between having a college degree and one's view on drilling for oil and natural gas. You find that the chi-squared statistic is 11.46 for these data. What is the p-value for this hypothesis test? Select one: O a. Less than 0.001 b. Between 0.001 and 0.005 O c. Between 0.005 and 0.01 d. Between 0.01 and 0.02 e. Between 0.02 and 0.05

Explanation / Answer

for above p value =0.0032

hence option B is correct between 0.001 to 0.005

Observed O Yes No Total Support 154 132 286 Oppose 180 126 306 Do not Know 104 131 235 Total 438 389 827 Expected E=rowtotal*column total/grand total Yes No Total Support 151.473 134.527 286 Oppose 162.065 143.935 306 Do not Know 124.462 110.538 235 Total 438 389 827 chi square =(O-E)^2/E Yes No Total Support 0.042 0.0475 0.090 Oppose 1.985 2.235 4.219 Do not Know 3.364 3.788 7.152 Total 5.391 6.070 11.4608

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.